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agingboomer wrote: »

My Pioneer SX-1250 is rated at 160 watts per channel into 8ohms. Anybody know what that is equivalent into 6ohms?

In the perfect world (i.e., infinitely capable power supply), roughly 210 watts (1.25 dB increase). It's kind of a zero sum game, though; it's a consequence of Ohm's law. 1 watt into a perfect (fixed) 8 ohm load translates into (about) 1.333 watts into a perfect 6 ohm load, or 2.0 watts a into a 4 ohm load. Achieving those 'translations' depends on the amplifier's ability to deliver, respectively, 1.333 or 2.0 times the current into the load, compared to its 8 ohm capability.
Practically speaking, the difference in power output is negligible. This does not mean that the quality of the signal reproduced at the load (loudspeakers) won't change. It could sound better or worse, given the vagaries of different loudspeakers, not to mention how well (or poorly) the nominal impedance of a given loudspeaker reflects its actual, frequency-dependent impedance and phase curves.
Sine wave power output capability, unfortunately, in and of itself, isn't a particularly useful specification when it comes to predicting how a particular amplifier will perform with a given loudpseaker load. It's even less useful in predicting how it will sound.

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