bi-wiring logic
aps1ngh
Posts: 36
Simple questions:
When bi-wiring a speaker from a single speaker, do you inhibit the function of the internal passive crossover of the speaker by removing the gold plate connecting the two sets of terminals on the back of the speaker?
And, when doing this and running a single signal output from the source into the speaker at two different locations (top posts for tweeter, bottom posts for mid-woofers), how exactly does this improve sound quality when the source is still a single output split into two speaker cables going to the same place they were before? (except before they were linked by a gold plate and now they're not...)
Please correct any mistakes I've made in my statement and help me to understand.
PS
This is in reference to my newly acquired used rt800i's.
When bi-wiring a speaker from a single speaker, do you inhibit the function of the internal passive crossover of the speaker by removing the gold plate connecting the two sets of terminals on the back of the speaker?
And, when doing this and running a single signal output from the source into the speaker at two different locations (top posts for tweeter, bottom posts for mid-woofers), how exactly does this improve sound quality when the source is still a single output split into two speaker cables going to the same place they were before? (except before they were linked by a gold plate and now they're not...)
Please correct any mistakes I've made in my statement and help me to understand.
PS
This is in reference to my newly acquired used rt800i's.
Post edited by aps1ngh on
Comments
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It doesn't change the crossover. If only a single amp or receiver is involved, then you are just effectively doubling the wire gauge.
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So if I am using AQ type 2 it's 22awg per strand, if I bi, I can get 11awg ?
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So if I am using AQ type 2 it's 22awg per strand, if I bi, I can get 11awg ?
Nope, that only works for gauges 5 through about 14. I suppose I shouldn't have used the term 'gauge'.
*Edit: Bonus point: 22awg bi = single 16 awg -
It doesn't change the crossover. If only a single amp or receiver is involved, then you are just effectively doubling the wire gauge.
I had come across this when I was researching the subject. Does this mean that ohm resistance is lowered when using two separate speaker wires? If so, still, what does that mean?
I'm kind of a newb. =x -
Thanks PT
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"He who fights with monsters should look to it that he himself does not become a monster. And when you gaze long into an abyss the abyss also gazes into you." Friedrich Nietzsche
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"In a single wired system unwanted mechanical and electrical resonances appear as distortion at both sets of speaker terminals. Due to the impedance of the speaker cables these distortions will not be entirely cancelled by the amplifier. Instead, they modulate between the two crossovers, degrading sound quality. With bi-wiring this interaction is minimised as signal distortion is 'seen' at the amplifier's output where it can be more effectively cancelled. Bi-wiring therefore presents a 'cleaner' signal at both the bass and treble speaker terminals, and because the high and low frequencies have already been separated, each has a minimal effect on the other - the bass does not overpower the delicate treble."
Question answered. Thank you. -
APS, the internal speaker crossover remains in effect and there's no significant difference created with biwiring(sometimes sarcastically termed "buywiring"). The wiring always has to divide at the latest by the time that it enters the crossover, since there are separate high and low frequency sections in the crossover. The only difference is that with the biwiring the division point is moved back to where it leaves the amplifier(but both wires continue to carry the full range of audio frequencies at that point)instead of at the speaker, but this has no audible effect. The claim from "Brilliance HiFi" is a collection of nonsensical illusions which have no basis in audio technology.
