Recalculating my output
ode
Posts: 58
I am using 8 ohm speakers on an AV receiver that is designed for 6 ohm speakers. If it is 80 watts per channel at 6 ohms do i have enough power with the 8 ohm speakers? How can I calculate that?
Post edited by ode on
Comments
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You are fine. The lower the ohm the speak is rated at, the more power you need to drive it. In reverse higher ohm= less power to drive the speak.RTi10
CSi5
RTi28
SVS PB12-ISD2
Denon 2106(pre/pro)
Adcom 5503(200x3)
Audioquest Diamondback ICS
Kimber Kable 8tc biwire(mains and center)
"Don't let your silly dreams fall in between the crack of the bed and the wall."
-J. James -
OK ty
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Originally posted by nellis8166
You are fine. The lower the ohm the speak is rated at, the more power you need to drive it. In reverse higher ohm= less power to drive the speak.
You mean higher impedance (higher amount of ohms), less amount of current.... lower impedance, more amount of current.
Making a lot of assumptions, driving a 4 ohm speaker with 50W and a 6 ohm speaker with 50W would, in theory, give you the same amount of loudness (dB's).
Ode - assuming you have a typical receiver, you'll have less power with the 8 ohm speakers. Whether you have enough power or not will come with listening and seeing if you have any noticeable distortion at your listening level.Brian Knauss
ex-Electrical Engineer for Polk -
Well my receiver is 80 wpc driving 4 R50's. Right now it's hard to tell in a movie because I have a POS little sony center but I just bought a CS1 which should be a better match with the R50's. Once it arrives and I have it set up I'll know if I need more juice.
