Speaker Distance And Time Delay

okiepolkie

My receiver has uses time delay in miliseconds for distance instead of feet intervals.

When determining speaker distance this way, what is the equation for conversion from ms to feet.

My simple understanding would be to muliply the spead of sound by the time delay.

For example: (761 feet/second)(10ms) = 7.61 feet

Is this right?

Thank you.

sowen010599

Delay time (msec) = Time-delayed distance (ft)/1.12

Based on a sound velocity of 340m/sec. at 15°C or 1120ft/sec. at 60°F

Example, 12' would be 10 milliseconds. 10' would be 9 milliseconds, etc.

Buuuuuuut, usually, if you are setting delays by the msec, you only work with the difference in distance between you and your fronts, and you and you rears.

Soooo, lets say your fronts (LF C RF), are 12' away from you, and your rear speakers are 6' away from you(get a tape measure), you need to delay the rears by making the sound take 6' worth more time to make it to your ears. That way everything arrives at the same time. So, in that case, you would set delay for 6', or 5.36 milliseconds.


761............... you're thinking MPH. The speed of sound is 761 miles per hour at sea level.

okiepolkie

Yeah, I realized that after your post, but didn't have time to reply until after you edited it.

My receiver also has a time delay for my center channel, so it will help there too.

Thanks for your help.

sowen010599

Ideally, you want your fronts and center equidistant from the listening position, and only use delays for the surrounds.

okiepolkie

Right. "Ideally". Mine doesn't work that way right now.

sowen010599

Well dang it! Why not!!??

hehe