How to figure out how many ohms speaker combos put out

phd500

What in the heck is the formula to figure out ohms. I would really appreciate it if someone out there could tell me, thanks.

juice21

R=V/I

where R=resistance (measured in ohms)
V=volts
I=current

Aaron

What are you trying to figure out exactly?

Aaron

phd500

Ok, so say I have two 5ohm subs wired in parellel can you give me a example on how to figure the math. I just want to make sure I get what your saying.

SONYTHEATER

IN SIMPLE TERMS IF YOU ARE TRYING TO WIRE MORE THAN ONE SPEAKER TO A SINGLE CHANNEL AND SAY THEY ARE BOTH 8 OHM IF THEY ARE WIRED SEARIES THAT IS (THE POS FROM YOUR AMP FEEDS SPEAKER A THAN THE NEG FROM A WILL FEED THE POS TO TO YOUR SECOUND SPEAKER B THAN THE NEG FROM B RETURNS TO THE AMP) YOU WILL GET A 4 OHM LOAD. ON THE OTHER HAND IF THE SAME SPEAKERS WAS WIRED PAIRALEL (ONE WIRE FEEDS THE POS AND NEG OF BOTH SPEAKERS ) YOU WILL GET A 16 OHM LOAD. ALSO SOMETHING TO KEEP IN MIND A LOWER RESISTANCE (LOAD IN OHMS) WILL MAKE YOUR AMP RUN HOTTER, BUT AT THE SAME TIME MOST WELL BUILT AMPS WILL ALMOST DOUBLE THEIR OUTPUT POWER FROM SAY 8 OHM TO A 4 OHM LOAD.SO IF YOUR AMP WILL HANDLE A 2 TO 4 OHM LOAD AND ITS RATED AT SAY 100 WATTS AT 8 OHMS RUNNING A 4 OHM LOAD IT WILL PRODUCE AROUND 200 WATTS,AND DOUBLE AGAIN AT 2 OHMS TO AOUND 400 WATTS. BUT YOU MUST BE CAREFULL DOING THIS SINCE MOST AMPS WILL ONLY TAKE A LOW LOAD FOR A VERY SHORT TIME BEFORE OVERHEATING OR BURNING UP... SORRY ABOUT THE BAD SPELLING BUT I HOPE THIS HELPS...

TroyD

....you don't need to shout, we hear ya brotha.

Troy

rayok275

Your Guy has it backwards.

paralell wiring gives you 1/2 of lowest ohm load.

series wiring gives you the sum.

Hope that helps!

Aaron

Rayok is right. You guys are backwards. Here are the equations for computing resistance where R1 and R2 are your resistances and Req is the equivalent resistance. Also remember that speakers present an impedance, not a simple resistance, so the resistance actually changes with frequency.

Req (series) = R1 + R2
Req (parallel) = 1/(1/R1 + 1/R2)

Aaron

SONYTHEATER

HAY SORRY GUYS I JUST LOOKED AT THAT I DID SAY IT BACKWARDS. THANKS FOR CORRECTING ME I PROBLEY WOLDENT OF REALIZED I DONE THAT...

Aaron

Dude, turn your CAPS LOCK off! It's like shouting on the internet and considered bad 'netiquette (internet etiquette).

Aaron

Anti Micah

And Aaron wins the prize for the clearest correct answer...make sure you follow his math very carefully.

His second statement is also true; however, hopefully, the carefully crafted crossover networks present on your speaker will make that a fairly moot point. All the poor tyke needs worry about is the resistance.